T
(−4)3=−4×,−4×,−4=−43=−64 a=56−337−4×,29−5=5333×,24 b=712+17×,94×,3×,5−5910×,5−7×,6=719×,912×,5−5910×,5−42=719×,912−10×,5−5+42=719×,92×,537(-4)^3=-4\times,-4\times,-4=-4^3=-64\ a=\dfrac{5^{6-3}}{3^{7-4}\times,2^{9-5}}=\dfrac{5^3}{3^3\times,2^4}\ b=\dfrac{7^{12+17}\times,9^{4\times,3}\times,5^{-5}}{9^{10}\times,5^{-7\times,6}}=\dfrac{7^{19}\times,9^{12}\times,5^{-5}}{9^{10}\times,5^{-42}}=7^{19}\times,9^{12-10}\times,5^{-5+42}=7^{19}\times,9^2\times,5^{37}(−4)3=−4×,−4×,−4=−43=−64 a=37−4×,29−556−3=33×,2453 b=910×,5−7×,6712+17×,94×,3×,5−5=910×,5−42719×,912×,5−5=719×,912−10×,5−5+42=719×,92×,537
Pour C il faut remarquer que (−4)−7=−4−7(-4)^{-7}=-4^{-7}(−4)−7=−4−7
car 7 est impair
Pour D rappelles-toi que (ab)n=anbn\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}(ba)n=bnan
